THE LUNG
Many say our lungs looks like a sponge, but have you ever wondered how it works? What it looks like? How you breathe?
What is the lungs?
Your lungs make up one of the largest organs in your body, and they work together with your respiratory system to allow you to take in fresh air (oxygen), get rid of carbon dioxide,to breathe and even to talk.
Where are the lungs located?
The lungs are located in the lung. You have two lungs, but they aren't the same size. Instead, the lung on the left side of your body is a bit smaller than the lung on the right. Did you know that the lungs is the largest organ in your body? This extra space on the left is the location of the heart. Both of the heart and the lungs work together in order to keep the body alive.
Have you ever wondered what the rib cage does? Well your lungs are protected by your rib cage. These ribs are connected to your spine in your back and go around your lungs to keep them safe. Beneath the lungs is the diaphragm that works with your lungs to allow you to breathe in (inhale) and out (exhale) air.
What does the lungs look like?
From the outside, lungs are pink and a bit squishy, like a sponge. In the lung, deep down at the bottom of the windpipe (trachea) there are two large tubes which seperates into the left and right lung. These tubes are called the main stem bronchi. Each main stem bronchus
(name for just one of the bronchi) branches off into tubes, like branches on a big tree. The tiny tubes are called bronchioles.
What happens to the lungs and diaphragm when inhaling and exhaling air?
When you're cleaning your room, or working out in the gym, you probably don't think about inhaling (breathing in). But every time you inhale air, body parts work together to help get air in your lungs without you thinking about it. As you breathe in, your diaphragm contracts and flattens out. This allows it to move down, so your lungs have more room to grow larger. the diaphragm isn't the only part that gives your lungs the room they need. Your rib muscles also lift the ribs up and outward to give the lungs more space for it to do its job.
When it's time to exhale (breathe out), everything happens in reverse. Your diaphragm relaxes and moves up, pushing air out of the lungs. Your rib muscles become relaxed, and your ribs move in again, creating a smaller space in your chest.
Your lungs are important for breathing . . . and also for talking! It is clear to state that the function of the lungs is a vital organ in the body and in order for humans and animals to survive, it is vital that the lungs is well functioned.
Friday, March 27, 2009
Wednesday, March 4, 2009
Limiting and excess reagent
WHAT IS LIMITING AND EXCESS REAGENT
Limiting reactant problems involves determining from the information given the inital quanities if the reactants in moles and then determining which one(s) are in excess and which reactant is the limiting reactant. Remember mole is KING.
An example of a limiting and excess reagent is a bike.
An image of a bike with 2 wheels and 1 frame.
The equation here is 2 wheels + 1 frame = 1 Bike
It is also called a 2:1 ratio.
Heres an question,
19g of C7H16 reacts with 113g of O2. Determine the mole of H2O in the following reaction.
C7H16 + 11O2 -> 7CO2 + 8H2O (balanced equation)
Must calculate the moles of C7H16 and O2.
n (C7H16)=m/Mr
n (C7H16)= 19g/100g/mol
n (C7H16)=0.19 mol
n (O2)=m/Mr
n (O2)=113g/32g/mol
n (O2)=3.35 mol
Next step is to determine which of the reactants is the limiting and the excess.
0.19 mol of C7H16 wants to react with 11/1 *0.19 mol = 2.09 mol of oxygen.
0.19 mole of C7H16 wants 2.01. Since 2.01 mol of oxygen is less than what i have (3.35 mol) it means oxygen is in EXCESS and C7H16 is the LIMITING. Due to the fact that C7H16 is the limiting, we bring the coefficient of C7H16 which is 1 to the other side of the equation. So to calculate the mole of H2O you place the coefficient of C7H16 under the coefficient of H2O and multiply it by the limiting mole of C6H17 which is 0.19 mol.
C7H16 + 11O2 -> 7CO2 + 8H2O
n (H2O)=8/1 *0.19 mole
n (H2O)=1.52 molw
The mole of H2O is 1.52 mol
Limiting reactant problems involves determining from the information given the inital quanities if the reactants in moles and then determining which one(s) are in excess and which reactant is the limiting reactant. Remember mole is KING.
An example of a limiting and excess reagent is a bike.
An image of a bike with 2 wheels and 1 frame.
The equation here is 2 wheels + 1 frame = 1 Bike
It is also called a 2:1 ratio.
Heres an question,
19g of C7H16 reacts with 113g of O2. Determine the mole of H2O in the following reaction.
C7H16 + 11O2 -> 7CO2 + 8H2O (balanced equation)
Must calculate the moles of C7H16 and O2.
n (C7H16)=m/Mr
n (C7H16)= 19g/100g/mol
n (C7H16)=0.19 mol
n (O2)=m/Mr
n (O2)=113g/32g/mol
n (O2)=3.35 mol
Next step is to determine which of the reactants is the limiting and the excess.
0.19 mol of C7H16 wants to react with 11/1 *0.19 mol = 2.09 mol of oxygen.
0.19 mole of C7H16 wants 2.01. Since 2.01 mol of oxygen is less than what i have (3.35 mol) it means oxygen is in EXCESS and C7H16 is the LIMITING. Due to the fact that C7H16 is the limiting, we bring the coefficient of C7H16 which is 1 to the other side of the equation. So to calculate the mole of H2O you place the coefficient of C7H16 under the coefficient of H2O and multiply it by the limiting mole of C6H17 which is 0.19 mol.
C7H16 + 11O2 -> 7CO2 + 8H2O
n (H2O)=8/1 *0.19 mole
n (H2O)=1.52 molw
The mole of H2O is 1.52 mol
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Limiting and excess reagent
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